2x/x-5+100/x^2-25-2x/x+5

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Solution for 2x/x-5+100/x^2-25-2x/x+5 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

100/(x^2)-((2*x)/x)+(2*x)/x-25-5+5 = 0

100/(x^2)+(2*x)/x-((2*x)/x)-25-5+5 = 0

100/(x^2)+(2*x)/x-25-5-2+5 = 0

100*x^-2 = 25 // : 100

x^-2 = 1/4

-2 < 0

1/(x^2) = 1/4 // * x^2

1 = 1/4*x^2 // : 1/4

4 = x^2

x^2 = 4 // ^ 1/2

abs(x) = 2

x = 2 or x = -2

x in { 2, -2 }

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